The area of the rectangle B = 18 sq unit.įinn imagines 1 more row of nine to find the total area of 9 × 9 rectangle. The area of the larger rectangle = 108 sq unit. The area of the rectangle A = 70 sq unit. The area of the small rectangle A = 70 sq unit. The area of the larger rectangle = 91 sq unit. The area of the rectangle B = 10 sq unit. The area of the rectangle A = 50 sq unit. The area of the small rectangle B = 10 sq unit. The area of the small rectangle A = 50 sq unit. The area of the larger rectangle = 60 sq unit. The area of the rectangle B = 32 sq unit. The area of the small rectangle B = 32 sq unit. The area of the larger rectangle = 72 sq unit. Eureka Math Grade 3 Module 4 Lesson 10 Homework Answer Key The area of the rectangle B = 27 sq unit.Īrea = 27. The area of the rectangle A = 90 sq unit. The area of the small rectangle B = 27 sq unit. The area of the small rectangle A = 90 sq unit. The area of the larger rectangle = 117 sq unit. Then, find the total area of the large rectangle by adding the areas of the 2 smaller rectangles. Label the side lengths of the shaded and unshaded rectangles. Explain your thinking.Įureka Math Grade 3 Module 4 Lesson 10 Exit Ticket Answer Key Then, find the sum of the areas of the 2 smaller rectangles and show how it relates to the total area. Explain how this could help him solve 9 × 8.īreak the 15 × 5 rectangle into 2 rectangles by shading one smaller rectangle within it. Vince imagines 1 more row of eight to find the total area of a 9 × 8 rectangle. The area of the rectangle B = 16 sq unit. The area of the rectangle A = 80 sq unit. The area of the small rectangle B = 16 sq unit. The area of the small rectangle A = 80 sq unit. The area of the larger rectangle = 96 sq unit. The area of the rectangle A = 60 sq unit. The area of the small rectangle B = 18 sq unit. The area of the small rectangle A = 60 sq unit. The area of the larger rectangle = 78 sq unit. The area of the rectangle A = 40 sq unit. The area of the small rectangle B = 8 sq unit. The area of the small rectangle A = 40 sq unit. The area of the larger rectangle = 48 sq unit. The area of the rectangle B = 21 sq unit. The area of the rectangle A = 35 sq unit. The area of the small rectangle B = 21 sq unit. The area of the small rectangle A = 35 sq unit. The area of the larger rectangle = 56 sq unit. Then, find the total area of the large rectangle by adding the areas of the two smaller rectangles. Label the side lengths of the shaded and unshaded rectangles when needed. The distance from Earth to Mars is 8× 10 10 meters.Engage NY Eureka Math 3rd Grade Module 4 Lesson 10 Answer Key Eureka Math Grade 3 Module 4 Lesson 10 Problem Set Answer Key If the sun is approximately 1.5× 10 11 meters from Earth, what is the approximate distance from Earth to Mars? It takes approximately 770 seconds for sunlight to reach Mars. To find the number of likes per person, divide the total number of likes by the total number of users: \(\frac\) If the company has approximately 8.9× 10 8 users of the social media, about how many likes is each user responsible for per year? Write your answer in scientific and standard notation.įirst, write 990 billion in scientific notation: 9.9× 10 11. There are about 3.22× 10 17 ants in the world!Ī certain social media company processes about 990 billion likes per year. =3.22× 10 17 By the first law of exponents =32.2× 10 16 By the first law of exponents To find the number of ants in the world, we need to multiply the world population by the known number of ants for each person: (7× 10 9)(4.6× 10 7 ). About how many ants are there in the world?įirst, write 7 billion in scientific notation: (7× 10 9). There are 4.6× 10 7 ants for every human on the planet. Engage NY Eureka Math 8th Grade Module 2 Lesson 10 Answer Key Eureka Math Grade 8 Module 2 Lesson 10 Example Answer Key
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